I needed a custom sort column for jquery tablesorter (http://tablesorter.com/docs/) for dates in the format of 12-Aug-2013 as the default tried to sort it as a string

Was quite complicated to work out, but think its done:

$.tablesorter.addParser({
    'id' : 'customDates',
    'is' : function(string) {
         return false;
         },
    'format' : function(string) {
        if (string == "") {
            return '';
        }
        var thedate = string.split('-');
        var monthint = {};
        monthint['Jan'] = "01";
        monthint['Feb'] = "02";
        monthint['Mar'] = "03"; 
        monthint['Apr'] = "04";
        monthint['May'] = "05";
        monthint['Jun'] = "06";
        monthint['Jul'] = "07";
        monthint['Aug'] = "08";
        monthint['Sep'] = "09";
        monthint['Oct'] = "10";
        monthint['Nov'] = "11";
        monthint['Dec'] = "12";
        var date_day = parseInt(String(thedate[0]));
        if (date_day.length == 1) {
            date_day = '0' + date_day;
        }
        var date_month = monthint[thedate[1]];
        var date_year = thedate[2];
        return date_year + date_month + date_day;
    },
    'type' : 'numeric'
    });

And then apply it to the table

$('table').tablesorter({
    'debug' : 'true', 
    'headers' : {
        0 : {
            'sorter' : 'customDates'
            } 
        } 
    });

By admin

2 thought on “jQuery tablesorter custom date sort”
  1. You are right, I replaced this section:

    var date_day = $.trim(String(thedate[0]));
    if (date_day.length == 1) {
    date_day = '0' + date_day;
    }
    var date_month = monthint[thedate[1]];
    var date_year = $.trim(thedate[2]);
    return date_year + date_month + date_day;

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